Calculations for Zulijans posts

[Diesel]

Exact Calculations

If this glitch is used on a stack of items, things become slightly more complex. The game will still drop as many items into the world as there are equipped arrows, but they will be grouped in stacks and, depending on the circumstances, a smaller stack may remain in the inventory.
Most of the stacks will contain as many copies of the item as were in the player's inventory (including any equipped copy), but unless the amount of arrows was an exact multiple of that number, the last stack dropped will contain a smaller number, namely the remainder needed to fill the exact number of arrows. The content of the last stack, whether it is smaller or identical to the others, is what will be removed from the player's inventory. Thus the process in the Step-by-Step Guide is really a special case with stacks of size 1.
If the last stack is not a smaller remainder, all copies of the item will be removed from the player's inventory immediately, even if one of the is equipped at the time and should be unequipped first. This can be exploited as well, to gain permanent effects from enchanted items.
Examples:
Amount of arrows equipped: 50
Items in Inventory: 60 Daedra hearts
Items dropped: 1 × 50 Daedra hearts
Left in Inventory: 10 Daedra hearts (=60-50)
(Note that no duplication takes place. This is the same as dropping an item normally and answering "50" to the question "How Many".)
Arrows: 50
Items: 1 Ring of Perfection
Dropped: 50 × 1 Ring of Perfection
Left: nothing (=1-1)
Arrows: 50
Items: 10 potions
Dropped: 5 × 10 potions
Left: nothing (=10-10)
Arrows: 50
Items: 6 Hammers
Dropped: 8 × 6 Hammers + 1 × 2 Hammers (=50)
Left: 4 Hammers (=6-2)

Just a little addition to Zuljians post

Sorry for spelling your name wrong in title Zul... :/